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1 - Yahoo!奇摩 搜尋結果
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1~990去2、3、5倍數後剩下的合
Sep 6th 2013, 21:12

發問 如題1~990中的正整數中,去掉2的倍數...所有數的總和 有個解法是這樣: 1/2*990^2*(1-1/2)(1-1/3)(1-1...1/15+1/10-1/30)+990(1-1-1-1+1+1+1-1)] =(1/2)[990^2(1-1/2...

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